(3x^2-5x+4)/(x-1)

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Solution for (3x^2-5x+4)/(x-1) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

(3*x^2-(5*x)+4)/(x-1) = 0

(3*x^2-5*x+4)/(x-1) = 0

3*x^2-5*x+4 = 0

3*x^2-5*x+4 = 0

DELTA = (-5)^2-(3*4*4)

DELTA = -23

DELTA < 0

1 = 0

1/(x-1) = 0

x belongs to the empty set

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